SOLVE and CHECK the following word problem. (6 marks) The length of a rectangle is 3 m greater than the width. The perimeter is 38 m. What
are the dimensions of the rectangle?

x = 8

Step-by-step explanation:

Let us take the breadth as 'x'

breadth = x

length = 3 + x

perimeter = 38m

perimeter of a rectangle = 2 ( l + b )

= 2( x + x + 3 ) = 38

4x + 6 = 38

4x = 38-6

x = 32/4

x = 8

breadth = 8

length = 11

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.