Rectangle LMNO has vertices L(–4,6), M(–1,6), N(–1,2), and O(–4,2). Suppose you first reflect this rectangle across the y-axis. Then, translate it down four units and to the left one unit. Where are the corresponding vertices L′M′N′O′ located?

L'(3, 2)

M'(0, 2)

N'(0, -2)

O'(3, -2)

Step-by-step explanation:

Vertices of a rectangle LMNO are L(-4, 6), M(-1, 6), N(-1, 2) and O(-4, 2).

If a point (x, y) is reflected across y-axis, rule to be followed,

(x, y) → (-x, y)

After reflection across y-axis new ordered pairs will be,

L(-4, 6)   → L"(4, 6)

M(-1, 6)   → M"(1, 6)

N(-1, 2)   → N"(1, 2)

O(-4, 2)  → O"(4, 2)

Then these points were translated 4 units down and 1 unit left,

Rule to be followed for the translation will be,

(x'', y'') → [(x' - 1), (y' - 4)]

By this rule vertices of the rectangle after translation will be,

L''(4, 6) → L'(3, 2)

M''(1, 6) → M'(0, 2)

N''(1, 2) → N'(0, -2)

O''(4, 2) → O'(3, -2)

1/8 3/16 3/4

step-by-step explanation:

you put them as all the same denominator and multiply

a, b, c, d are correct.

step-by-step explanation:

we have g(x) = 3 and are required to find which option is a translation of g(x).

now, 'translation' is a transformation which means to shift the function in any direction and the general form of translation is g(x) + k, where k is any real number.

so, according to the options we see that all are correct as they satisfy the general form of translation.

also, it can be seen from the graph below that the function g(x) = 3 is shifted from its position in all the four options.