To test H0: μ=100 versus H1:≠100, a simple random sample size of nequals=24 is obtained from a population that is known to be normally distributed. Answer parts (a)-(d).(a) If x =104.2 and s=9.6, compute the test statistic. t= _ (Round to three decimal places as needed.)(b) If the researcher decides to test this hypothesis at the α=0.01 level of significance, determine the critical values. The critical values are __ .(c) Draw a t-distribution that depicts the critical region(s). Which of the following graphs shows the critical region(s) in thet-distribution?(d) Will the researcher reject the null hypothesis?

a) Test statistic = 1.960

b) The critical values include -2.50 and 2.50.

The critical regions of rejection are thus

t < -2.50 or t > 2.50

c) The sketch of the curve is presented in the attached image to this solution. The shaded parents indicate the rejection regions.

d) The t-statistic obtained (1.96), lies within the acceptance region (-2.50 ≤ x ≤ 2.50), we fail to reject the null hypothesis.

Step-by-step explanation:

a) Test statistic is computed using the expression

t = (x - μ₀)/σₓ

x = Sample mean = 104.2

μ₀ = the standard we are comparing Against

σₓ = standard error of the mean = (σ/√n)

σ = 9.6

n = Sample size = 24

σₓ = (9.6/√24) =

t = (0.425 - 0.35) ÷ 0.07816

t = 1.9595917942 = 1.960

b) To obtain these critical values, we first find the degree of freedom

Degree of freedom = n - 1 = 24 - 1 = 23

The critical values for significance level of 0.01 and degree of freedom of 23 is given as

t(0.01, 23) = 2.50

So, since the test is two-tailled (we are testing in both directions; greater than or less than), the regions of rejection include

t < -2.50 and t > 2.50

c) since the test is two-tailled (we are testing in both directions; greater than or less than), the regions of rejection include

t < -2.50 and t > 2.50

The t-distribution curve is very similar to the normal distribution curve. The t-distribution curve is also a bell shaped curve, but it is heavier at the limits indicating that the t-distribution favours outliers more than the normal distribution.

The sketch of the curve is presented in the attached image with the shaded regions indicating the rejection region.

d) Since the t-statistic obtained (1.96), lies within the acceptance region (-2.50 ≤ x ≤ 2.50), we fail to reject the null hypothesis.

Hope this Helps!!!

honesty mood

step-by-step explanation:

total amount of money that he should pay if he has not used his duty free exemption is $98

step-by-step explanation:

given a united states citizen returning to the states declares the following items at the customs office: 3 shirts at $8.50 each 2 dresses at $27.50 each 1 pair of gold cuff links at $17.50 per pair. we have to find how much he pay

cost of 3 shirts if one cost at $8.50 is

cost of 2 dresses if one cost at $27.50 is  

cost of 1 pair of gold cuff at $17.50

so, total amount of money that he should pay if he has not used his duty free exemption is   $25.5+$55+$17.50=$98