Triangle BAC was dilated from triangle BDE at a scale factor of 2 what proportion proves that sin

The answer is 3/3.61 = 6/7.22 (C)  because I got the three other choices incorrect on my quiz.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

1. minimum

2. 6400

3. eight

hope this !