Val's whole-house central air conditioner uses 3,500 watts when running. Val runs the AC 6 hours per summer day. Electricity costs (18 cents)/(1 kilowatt-hour). How much does Val's AC cost to run for a summer month of 30 days?

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11,340 cents

Step-by-step explanation:

• Step I)

Power of the air conditioning = 3500 W

Our first step to calculating energy consumption is:

Converting it into kilowatts:

1000 W = 1 kW

3500 W = 3.5 kW

• Step II)

Take the time the appliance was used, in hours:

Time is taken = 6 hours per day

For 30 days,

Time = 6 × 30

= 180 h

• Step III)

Calculate the energy consumption by multiplying the power rating of the appliance with the time it was used (in hours).

E = 3.5 kW × 180 h

= 630 kWh

• Step IV)

For billing the amount:

Multiply the energy consumed by the cost per kWh (often written as "unit")

Cost = 18 cents per kWh

Total cost = 18 × 630

= 11, 340 cents

Thus, his AC costs him 11, 340 cents.

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

answer: its c because when it has a magnet next to it it will move away from the mixture. hope this

step-by-step explanation: