Hi someone please help me I'm not sure how to do thi If the longer base of triangle XYZ is three times the length of the shorter base, a, what is the length of the hypotenuse in terms of the shorter base?

The length of the hypotenuse is √(10)*a

Step-by-step explanation:

Remember the Pythagorean theorem.

If b is the larger base, and a the shorter base, and H is the hypotenuse:

a^2 + b^2 = H^2

now, we know that b = 3*a.

(3*a)^2 + a^2 = H^2

10*a^2 = H^2

√(10)*a = H

Then we have the length of the hypotenuse in terms of the shorter base, B.

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk