P(2, 2), Q(1, -3), R(-4, 2), S(-3, 7) Using the information above, answer the following questions. Find the length of RS Find the length of SP Find the length of PQ Find the length of RQ Use this information to determine if the quadrilateral a parallelogram.

Yes the Quadrilateral is a Parallelogram.

Step-by-step explanation:

A parallelogram can be defined as a quadrilateral i.e a geometric shape with four sides that has opposite sides parallel and equal in length.

From the question, we are given the following points

P(2, 2), Q(1, -3), R(-4, 2), S(-3, 7)

Given points: (x1, y1) and (x2, y2)

The formula would be

√(x2 - x1)² +(y2 - y1)²

a) P(2, 2), Q(1, -3)

Length PQ = √(1 - 2)² +(-3 - 2)² = √-1² + -5² = √26

b) R(-4, 2), S(-3, 7)

Length RS = √(-3 - (-4))² + (7 - 2) ² = √ 1² + 5² = √26

c) R(-4, 2), Q(1, -3)

Length RQ = √(1 - (-4))² + (-3 - 2)² = √5² + 5² = √(25 + 25) = √50

d) S(-3, 7), P(2, 2)

Length SP = √(2 - (-3))² + (2 - 7)² = √5² +(-5)² = √(25 + 25) = √50

From the above solution, we can see that

Length PQ = Length RS

Length RQ = Length SP

This means the opposite sides are parallel and equal in length, hence it is a Parallelogram.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2