What are the degree and zeros of the polynomial f(x)=(x-1)^2(x+1)

degree 3  zeros -1 and 1

Step-by-step explanation:

This is a third degree polynomial

f(x)=(x-1)^2(x+1)

It has an x^2 from the first term and an x from the second term for x^3

The zeros are x-1 =0  which means x=1

x+1 = 0  x=-1

Step-by-step explanation:

(x-1)²(x+1) = x³-2x²+x+x²-2x+1

                 = x³-x²-x+1

                 = x²(x-1)-x+1

                 = x²(x-1)-(x-1)

                 = (x²-1) (x-1)

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2