In circle P, EG and FH are diameters.
What is m EH?

= 130°

Step-by-step explanation:

Angles subtended at the center by the arcs and are ∠HPG and  ∠EPF.

Since these angles are the vertical angles both will be equal.

m∠HPG ≅ m∠EPF

3x - 10 = 2x + 10

3x - 2x = 10 + 10

x = 20

Therefore,

                               = 50°

Similarly = 50°

In the same way angles subtended at the center will be equal.

m∠EPH ≅ m∠FPG

and

Since °

Therefore, measure of arc EH = 130°

hope this .

r3t40