What are the chances of choosing a black marker out of a bag containing 3 red markers, 5 blue markers, 3 yellow markers, and 4 black markers? What is the probability of choosing two black markers if the first marker is put back before the second is drawn?

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Step-by-step explanation:

It is given that,

Number of red markers = 3

Number of blue markers = 5

Number of yellow markers = 3

Number of black markers = 4

Total markers = 3 + 5 + 3 + 4 = 15

Probability of getting a black marker is

Probability of choosing two black markers if the first marker is put back before the second is drawn, is

Required probability  

Therefore, the  probability of choosing two black markers if the first marker is put back before the second is drawn, is .

answer: the resulting cross section is a rectangle. solution: a plane parallel to the base of a triangular prism will intersect a cross section that is the same shape as its bases. so the cross section is a triangle.

step-by-step explanation:

the correct answer is c

good luck love