Given the system of linear equations. x=y+3 y=-4x-3 Part A: Solve the linear system of equations by graphing Part B: Use substitution to solve the linear system of equations Part C: Use addition to solve the linear system of equations In your final answer, include all of your work, the graph of the equations and the solution.

see below

Step-by-step explanation:

x=y+3

Subtract 3 from each side

x-3 = y

y = x-3

y=-4x-3

We have both equations in slope intercept form

y = mx +b where m is the slope and b is the y intercept

graph is below

They both have the same y intercept so they intersect at (0,-3)

Substitution

x=y+3

y=-4x-3

Substitute the second equation into the first equation

x=y+3

x = -4x-3 +3

x = -4x

Add 4x to each side

5x =0

x=0

y = -4x-3

y = 0-3

y = -3

(0,-3)

Additon

x=y+3

Subtract y from each side

x-y = 3

y=-4x-3

Add 4x to each side

4x+y =-3

Add the equations together to eliminate y

x-y = 3

4x+y =-3

-----------------

5x +0y =0

5x = 0

x=0

Now solve for y

y = -4x-3

y = 0-3

y = -3

(0,-3)

a, b, c, d are correct.

step-by-step explanation:

we have g(x) = 3 and are required to find which option is a translation of g(x).

now, 'translation' is a transformation which means to shift the function in any direction and the general form of translation is g(x) + k, where k is any real number.

so, according to the options we see that all are correct as they satisfy the general form of translation.

also, it can be seen from the graph below that the function g(x) = 3 is shifted from its position in all the four options.