The sum of the digits of a two-digit number is 12. If the digits are
are interchanged
the number is increased by 36. Find the
number

Let us assume x and y are the two digits of the number.

Therefore, two-digit number is = 10x + y and the reversed number = 10y + x

Given:

x + y = 12

y = 12 – x 1

Also given:

10y + x - 10x – y = 18

9y – 9x = 18

y – x = 2 2

Substitute the value of y from eqn 1 in eqn 2

12 – x – x = 2

12 – 2x = 2

2x = 10

x = 5

Therefore, y = 12 – x = 12 – 5 = 7

Therefore, the two-digit number is 10x + y = (10*5) + 7 = 57

Can you mark me brainliest? Thank you and be safe! :D

-Eli

Hmmm pretty sure it is 57, after doing the math.

i believe that the answer is

b. y-1=-2(x-4)

hope this !