Answers: 2
Mathematics, 21.06.2019 16:10
To find the extreme values of a function f(x.y) on a curve x-x(t), y y(t), treat f as a function of the single variable t and use the chain rule to find where df/dt is zero. in any other single-variable case, the extreme values of f are then found among the values at the critical points (points where df/dt is zero or fails to exist), and endpoints of the parameter domain. find the absolute maximum and minimum values of the following function on the given curves. use the parametric equations x=2cos t, y 2 sin t functions: curves: i) the semicircle x4,y20 i) the quarter circle x2+y-4, x20, y20 b, g(x,y)=xy
Answers: 2
Mathematics, 21.06.2019 19:30
[15 points]find the quotient with the restrictions. (x^2 - 2x - 3) (x^2 + 4x + 3) Γ· (x^2 + 2x - 8) (x^2 + 6x + 8)
Answers: 1
Mathematics, 21.06.2019 21:40
Atransformation t : (x,y) (x-5,y +3) the image of a(2,-1) is
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Mathematics, 21.06.2019 22:20
Atriangle has verticals at b(-3,0), c(2,-1), d(-1,2). which transformation would produce an image with verticals bβ(-2,1), cβ(3,2), dβ(0,-1)?
Answers: 2
Simplify the expression (x - 2y) + (3x + 4y)...
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