I am stuck on 14 and 15 as they do not have a straight line going through to help me, anybody know how to ?? thanks !

  14. x=21, GK=167°, HJ=98°, HGJ=262°, GKJ=201°

  15. x=9, AD=108°, BC=23°, DC=139°, DBC=221°

Step-by-step explanation:

In each case, the sum of the arcs around the circle is 360°.

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14. 61 +(5x -7) +34 +(9x -22) = 360

  14x = 294 . . . . . subtract 66, simplify

  x = 21 . . . . . . . . divide by 14

  (5x -7) = 98

  (9x -22) = 167

x = 21arc GK = 167°arc HJ = 98°arc HGJ = 360° -98° = 262°arc GKJ = 167° +34° = 201°

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15. 90 +(2x +5) +(17x -14) +(12x) = 360

  31x = 279 . . . . subtract 81, simplify

  x = 9 . . . . . . . . divide by 31

  (2x+5) = 23

  (17x -14) = 139

  (12x) = 108

x = 9arc AD = 108°arc BC = 23°arc DC = 139°arc DBC = 360° -139° = 221°

Answer: d. 39 cmin the diagram, the approximate length of the minor arc de is 39 centimetres.step-by-step explanation: the formula for the length of an arc in a circle is as displayed below.let the length of the minor arc de = xx = 2( pi )r × angle of sector / 360°from this, we will substitute the values given from the problem into the formula to obtain the length of the minor arc de.x = 2( pi )r × angle of sector / 360°r = radius = 25cmpi as an approximate value = 3.14angle of sector = 120°x = 2( 3.14 )( 25 ) × 120° / 360°x = 157 × 1 / 4x = 39.25x = 39 ( rounded to the nearest whole number as an approximate value )