What is the equation, in slope-intercept form, of the line that is perpendicular to the line y-4= -2/3 (x-6) and passes through the point (-2, -2)? Oy=-2/3x-10
Oy=-2/3x+10
Oy=x3/2x-1
O y=3/2x+1

The answer is option D.

Equation of a line is y = mx + c

m = slope

c = intercept on y axis

y-4= -2/3 (x-6)

y = -2/3x + 4 + 4

y = -2/3x + 8

From the above equation

m= -2/3

Since the lines are perpendicular the slope of the line is the negative inverse of the original line.

so m = 3/2

Equation of the line using point (-2 , -2) is

y + 2 = 3/2(x+2)

y = 3/2x + 3 - 2

y = 3/2x + 1

That's the last option

Hope this helps

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step-by-step explanation: