A 1000 pound boat sits on a ramp inclined at 22 degrees. How much force is pulling down the ramp, and how much force is pressing on a line perpendicular to the ramp?

The force pulling down the ramp is 374.6 lb

The force pressing on a line perpendicular to the ramp is 927.1 lb

Step-by-step explanation:

Given;

weight of boat (mg) , w = 1000 lb

angle of inclination of the ramp, θ = 22 degrees.

The force pulling the boat down, which is 'mg' has two components; the parallel component of the force which is pulling down the ramp and the vertical component of the force which is force pressing on a line perpendicular to the ramp

Parallel component of the force, F = mgsinθ

                                                      F = wsinθ

                                                      F = 1000 sin(22)

                                                      F = 1000 x 0.3746

                                                     F = 374.6 lb

Vertical component of the force which is force pressing on a line perpendicular to the ramp.

F = mgCosθ

F = wCosθ

F = 1000 x Cos(22)

F = 1000 x 0.9271

F = 927.1 lb

step-by-step explanation:

4th option is correct xy=-10

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