A model rocket is launched from ground level. Its height, h meters above the ground, is a function of time t seconds after launch and is given by the equation h=-4.9t^2+68.6t What would be the maximum height, to the nearest meter, attained by the model?

240 m to nearest meter.

Step-by-step explanation:

h = -4.9t^2 + 68.6t

We need to convert this to vertex form to find the maximum value of h:

h = -4.9(t^2 - 14t)

h = -4.9[(t - 7)^2 - 49]

h =  -4.9(t - 7)^2 + 240.1

So maximum height is when t = 7 and it's 240.1 meters.

answer: the first one

step-by-step explanation: use a calculator and divide the minutes by the dollars.

step-by-step explanation:

no, her answer is not correct.   we square the lengths of all sides and then determine whether the pythagorean theorem holds here:

9² + 15² = 306.   this is not equal to the square of the longest side ( that square being 395.   answer c is correct.