For each day of last year, the number of vehicles passing through a certain intersection was recorded by a city engineer. One objective of this study was to determine the percentage of days that more than 425 vehicles used the intersection. Suppose the mean for the data was 375 vehicles per day and the standard deviation was 25 vehicles.(A) What can you say about the percentage of days that there were between 325 and 425 vehicles that used the intersection? Assume you know nothing about the shape of the relative frequency distribution.(B) What can you say about the percentage of days that more than 425 used the intersection?Assume you know nothing about the shape of the relative frequency distribution.(C) What is your answer to part (A) if you know that the relative frequency distribution for the data is mound-shaped?(D) What is your answer to part (B) if you know that the relative frequency distribution for the data is mound-shaped?(E) What can you say about the percentage of days that there were between 300 and 425 vehicles that used the intersection? Assume that the frequency distribution is mound shaped.

in if you ask questions, the points are taken from your total and given to the one who answered it..

so if i have 30 points and i ask a question for 5 points, then when someone asks a question i will lose 5 points and the answerer earns 5

happy to

the answer to your question is c.)   volcanoes built the mountains and earthquakes tore them down.

step-by-step explanation:

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.

i would love   to but there is no graph shown

step-by-step explanation:

i am so sorry