= 115°![\frac{1}{2}[m(\widehat{AB}+m(\widehat{FC})]](/tpl/images/0701/4226/553cd.png)
---------(1)
= 40°
= 100° + 60° + 30°![\frac{1}{2}[40+190]](/tpl/images/0701/4226/31b6a.png)
I need help please!
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Answers: 2
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