A leaky pool loses 2 and one-fourth inches of water each day. Jermaine and Mildred are asked to determine the change in the amount of water in the pool over 5 days. Jermaine's Solution Mildred's Solution 5 (Negative 2 and one-fourth) = 5 (negative 2 minus one-fourth) = negative 10 minus one-fourth = negative 10 and one-fourth 5 (Negative 2 and one-fourth) = 5 (negative 2 minus one-fourth) = negative 10 minus StartFraction 5 over 4 EndFraction = negative 11 and one-fourth Which describes the reasoning used to determine whose solution is correct?

(x, y)→(x − 8, y − 7)

step-by-step explanation:

enjoy!

i dont get the question

step-by-step explanation:

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497

total of apples - take away four

6-4 = 2

answer is 2 apples