Could someone please help me with this: Solution set of lx^2+mx+n=0 is?

Quadratic equations have the solution

x = [-b +-sqr root(b^2 -4ac)] / 2a

In the given equation a = l; b = m and c = n So,

x = [-m +-sqr root(m^2 -4*l*n)] / 2*l

Step-by-step explanation:

i think is g(1)=-1.

hope that i can

ℓσℓ ιт ∂σит тяσυвℓє мє αт αℓℓ ιм gℓα∂ тσ нєℓρ ρρℓ συт

ωє ιт ¢αи вє ωяιттєи αѕ

step-by-step explanation:

нσρє ι ¢συℓ∂ нєℓρ уσυ συт