Tanya has several bills in her wallet. She has a total of $40. If she has one more $5 bill than $10 bills, and two more $1 bills than $5 bills, how many of each does she have?

no. of $10 bill =2

no. of $5 bill = 3

no. of $1 bill = 5

Step-by-step explanation:

Let the no. of $10 bill be x

Total value of $10 bill = $10*no. of $10 bill = $10x

Given that

Tanya has one more $5 bill than $10 bills

Thus, no. of $5 bill = x+1

Total value of $5 bill = $5*no. of $5 bill = $5(x+1)

Also Given

she has two more $1 bills than $5 bills

no. of $1 bill = no. of $2 bill + 2 = x+1+2 = x+3

Total value of $2 bill = $2*no. of $2 bill = $1(x+3).

Therefore, total value of all the bill sin terms of x

= 10x + 5(x+1) + 1(x+3)

Given that she has total of $40,

then

10x + 5(x+1) + 1(x+3) = 40

10x + 5x+5 + x+3 = 40

=> 16x + 8 = 40

=> 16x= 40-8=32

=> x = 32/16= 2

Thus,

no. of $10 bill = x = 2

no. of $5 bill = x+1 = 2+1= 3

no. of $1 bill = x+3 = 2+3=5

y=mx+

the equation for this situation is y=122+45. to solve the equation you would add 45 and 122 to get a total of 167lbs. in conclusion, grace's weight eight weeks ago was 167lbs.