What is the converse of the conditional statement? Ifxis even, then x + 1 is odd.
If x is not even, then x +1 is not odd.
If x + 1 is odd, then x is even.
If x + 1 is not odd, then x is not even.
O lfx is even, then x + 1 is not odd.

  If x + 1 is odd, then x is even.

Step-by-step explanation:

The converse of the statement ...

  if P, then Q.

is ...

  if Q, then P.

Here, we have P="x is even" and Q="x+1 is odd". The converse statement is ...

  if x+1 is odd, then x is even.

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

3030 ur welcome

step-by-step explanation: