A theorem states that if f is continuous on an interval I that contains one local extremum at c and if a local minimum occurs at c, then f(c) is the absolute minimum of f on I, and if a local maximum occurs at c, then f(c) is the absolute maximum of f on I. Verify that the following function satisfies the conditions of this theorem on its domain. Then, find the location and value of the absolute extremum guaranteed by the theorem. f(x)= -xe^-x/4 The function f(x) = -xe^-x/4 has an absolute extremum of Q at x=.?

Step-by-step explanation:

To find the extremum of the function, you need to take the first derivative.

This derivative = 0 if and only if x - 4 = 0, hence the extremum is at x = 4

To consider if it is local max or min, you need to consider the act of the function before and after x = 4 by making a table.

                                       4                                      

f(x)                 -                       0                +

Hence x =4 is a  local min.

what is all that apply?

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17