Kite ABCD (a quadrilateral with two pairs of adjacent equal sides) has coordinates A\(0,7), B (1,0),\ C (12,-2), and D (7,8). What is the area of ABCD, given that the area of a kite is equal to half the product of its diagonals? PLEASE HELP DUE IN FIVE MINUTES

Area=45

Step-by-step explanation:

Area=AC*BD/2=V12^2+(-9)^2*V6^2+8^2=(V144+81)*V36+64/2=V225*6/2=15*6/2=45

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,