Pls help

Isosceles Triangle

Step-by-step explanation:

ΔABC is an isosceles triangle. At ∠C, we have 180°. We are given 50° and 80° on the very right from the vertical angle. All we have to do is find that missing side.

50+x+80=180

x+130=180

x=50

Now that we know ∠C, we can find the missing angle.

80+50+x=180

130+x=180

x=50.

Overall, e have the angles 50°, 50°, and 80°. This is the property of an isosceles triangle. In an isosceles triangle, there are 2 sides with the same length and 2 angles that are the same. The 50° would be the 2 bottom angles and the 80° would be the top angle. Therefore, ΔABC is an isosceles triangle.

b) angle ABC = angle BCE (corresponding angles)

Angle ACB = 180 - 80-50 = 50° (angles in a straight line)

So. Angle BAC = 180 - 80 - 50= 50° ( angles in a triangle)

a) This triangle is an isosceles triangle because two angles ACB and BAC are equal.

srry idk

step-by-step explanation: