If angle A is congruent to itself by the Reflexive Property, which transformation could be used to prove ΔABC ~ ΔADE by AA similarity postulate? triangles ABC and ADE, in which point D is between points A and B and point E is between points A and C Translate triangle ADE so that point D lies on point B to confirm ∠D ≅ ∠B. Translate triangle ADE so that point B lies on point E to confirm ∠B ≅ ∠E. Dilate ΔABC from point A by the ratio segment AD over segment AB to confirm segment AD ~ segment AB. Dilate ΔABC from point A by the ratio segment AE over segment AC to confirm segment AE ~ segment AC.

Translate triangle ABC so that point C lies on point E to confirm ∠C ≅ ∠E.

Step-by-step explanation

The reflexive property states that any real number, a, is equal to itself i.e a = a. Therefore for both triangles, the value of angle A is the same. We can say that the two triangles are congruent at angle A.

To prove that ΔABC ~ ΔADE by AA similarity postulate,  the congruency may be in angles (AAA) or two sides that include point A have the same length (SAS). So, Translate triangle ABC so that point C lies on point E to confirm ∠C ≅ ∠E.

d. it is a convex pentagon because it has five sides and none of the sides would extend into the inside of the polygon.

step-by-step explanation: