IfA={1,2,3,4} B={2,4,6} C={1,3,5,7} andU={1,2,3,4,5,6,7} then B−C

Step-by-step explanation:

We are given the following sets:

To find:

Solution:

Here, we are given 4 sets,

The universal set, U and its 3 proper subsets A,B and C.

Proper subsets are the subsets which have at least one element which is extra in the super set.

Now, let us have a look at the definition of 'minus' in terms of sets.

Minus is defined as the set of elements which contains the elements of first set which are not present in the other set.

OR

The common elements are not written.

For example:

P = {10,20,30}

Q = {10,40,70}

P - Q = {20,30}

Common element(s) of  P Q = {10} is/are not written in P-Q.

Here, there are no common elements in B and C.

OR

is the correct answer.

abde or 1,2,4, 5 is the answer

step-by-step explanation:

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841