Please Help!! A ship leaves port at noon at a bearing of 293°. The ship’s average rate of speed over this time is 18 miles per hour.

Describe the location of the ship at 3:30 p. m. by writing a vector in component form. Then explain what these components mean in terms of the scenario.

Drag a value into each box to correctly complete the statements.

Ok, the speed is 18 mph.

The angle is 293°, and we usually measure the angles from the x-axis, so we can write our coordinates of velocity as:

Vx = 18mph*cos(293°) = 7mph.

Vy = 18mph*sin(293°) = -16.6mph.

Then we can write this as a vector (Vx, Vy)

Velocity = (7mph, -16.6mph)

Now, for the position, we can integrate over time, and using that the position (0,  0) is the starting point of the ship, we have that the position vector is:

P(t) = (7mph*t, -16,6mph*t)

Where t is the number of hours after the ship leaved the port.

If t = 0 is 0:00pm, then at 3:30pm we have t = 3 hours and 30 minutes

one hour has 60 minutes, then 30 minutes is equivalent to 0.5 hours.

Then 3:30pm we have t = 3.5 houes.

Now we replace this in the position vector and the location of the ship at 3:30pm is:

P(3.5h) = (7mph*3.5h, -16.6mph*3.5h) = (24.5 mi, -58.1 mi)

Where the first component describes the displacement in the x-axis, and the second component describes the displacement in the y-axis.