Find the work done in emptying a cylindrical tank filled with water. The water is being pumped out from the 6 top. The tank has a diameter of 4 feet and is 6 feet tall. The tank is on ground level. Water is 62.4 lbs/ft

908360.67 lb-ft

Step-by-step explanation:

height of tank= 6 ft

diameter of the tank = 4 ft

density of water p = 62.4 lbs/ft

A is the cross sectional area of the tank

A =

where r = diameter/2 =  4/2 = 2 ft

A = 3.142 x = 12.568 ft^2

work done = force x distance through which force is moved

work = F x d

Force  due to the water = pgAh

where g = acceleration due to gravity = 32.174 ft/s^2

Force  = 62.4 x 32.174 x 12.568 x 6 =  151393.44 lb

work done = force x distance moved

work = 151393.44 x 6 = 908360.67 lb-ft

3 1/3 x 2 3/5 = 8 2/3

step-by-step explanation:

just multiply the first number by the second number to get your answer.