Please show you work for both 5 and 6!

5-c)  6-c)

Step-by-step explanation:

5 c)= (a^4)^(1/3)= a^(4*1/3)=a^(4/3)

6. At the beginning of 1st year the total value on the bank account=500 USD

At the end of 1-st year the total value is 500 USD +3% from 500 USD=

500+500*0.03= 500*1.03

At the end of 2-nd year the total amount is 500*1.03+3% from 500*1.03=

500*1.03^2

Similarly at the end of the 3-rd year the total amount is 500*1.03^3

Finally at the end of fourth year the total amount is 500*1.03^4

homozygous. one is homozygous, while two is heterozygous.