Ash and Misty are both travelling by train. Ash's train travels 80 km in 50 minutes. Misty's train travels 160 km. It leaves at 12:35 and arrives at 15.05. Work out the difference, in km/h, between the average speed of their trains.

∆v = 32 km/h

the difference, in km/h, between the average speed of their trains is 32 km/h.

Step-by-step explanation:

For Ash's Train;

Distance travelled d1 = 80km

Time taken t1 = 50 minutes = 5/6 hour

Average speed = distance travelled/time taken

v1 = d1/t1

Substituting the values;

v1 = 80/(5/6)

v1 = 96km/h

For Misty's train;

Total distance travelled d2 = 160 km

Time taken t2 = 15:05 - 12:35 = 2 hours 30 minutes

t2 = 2.5 hours

v2 = d2/t2 = 160/2.5

v2 = 64 km/h

the difference, in km/h, between the average speed of their trains is;

∆v = v1 - v2 = 96km/h - 64 km/h = 32 km/h

∆v = 32 km/h

the difference, in km/h, between the average speed of their trains is 32 km/h.

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step-by-step explanation:

the x's and the y's both go up the same amount each time, therefore it will be a linear function because it will go in a straight line when drawn on a graph.

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