which of the following are solutions to the equation below check all that apply 2x^2 +6x = 20 A) 2 B) -10 C) 1 D) 20 E) -5 F) -2

A. x = 2

E. x = -5

Step-by-step explanation:

Step 1: GCF

2(x² + 3x) = 20

x² + 3x = 10

Step 2: Complete the Square

x² + 3x + 9/4 = 10 + 9/4

(x + 3/2)² = 49/4

Step 3: Solve

√(x + 3/2)² = √49/4

x + 3/2 = ±7/2

x = -3/2±7/2 or x = -5, 2

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

just sum

10 + 10 = 20