The mapping of DEFG to D'E'F'G' is shown. 2 parallelograms have identical side lengths and angle measures. The second parallelogram is a reflection of the first. Which statements are true regarding the transformation? Check all that apply. EF corresponds to E'F'. FG corresponds to G'D'. ∠EDG Is-congruent-to ∠E'D'G' ∠DEF Is-congruent-to ∠D'E'F' The transformation is not isometric. The transformation is a rigid transformation.

(A)EF corresponds to E'F'

(C)∠EDG Is-congruent-to ∠E'D'G'

(D)∠DEF Is-congruent-to ∠D'E'F'

(F)The transformation is a rigid transformation.

Step-by-step explanation:

Given:

The following applies:

Now, a rigid transformation is a transformation of the plane that preserves length. Since the two parallelograms have identical side lengths:

Note that a reflection is an isometric transformation. Therefore the statement "The transformation is not isometric" is INCORRECT.

FG and GD are adjacent sides, therefore they may not necessarily be congruent. Thus FG does not corresponds to G'D'

i am sure it will be 90 degrees.

step-by-step explanation:

the discriminant is 64 + 4*1*12 = 112

this is prime.

step-by-step explanation: