For which pair of functions is the vertex of k(x) 5 units below the vertex of f(x)?
A. f(x) = x2 and k(x) = (x + 5)2
B. f(x) = x2 and K(x) = x2 - 5
c. f(x) = x2 and k(x) = x2 + 5
D. f(x) = x2 and k(x) = (x - 5)2

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

seems like d

step-by-step explanation:

there is no grid

step-by-step explanation:

what graph

step-by-step explanation: