HURRY) A game at the fair involves a wheel with seven sectors. Two of the sectors are red, two of the sectors are purple, two of the sectors are yellow, and one sector is blue. Landing on the blue sector will give 3 points, landing on a yellow sector will give 1 point, landing on a purple sector will give 0 points, and landing on a red sector will give –1 point. If you take one spin, what is your expected value?
What changes could you make to values assigned to outcomes to make the game fair?
Prove that the game would be fair using expected values.

The game is not fair

Step-by-step explanation:

A wheel with seven sectors:

Red Sectors  = 2   |  Probability  = 2/7

Purple sectors  = 2  |  Probability  = 2/7

Yellow sectors  = 2 |   Probability  = 2/7

Blue sectors  = 1  |  Probability  = 1/7

Landing on the blue sector will give 3 points,  => 3 * 1/7  = 3/7    points

landing on a yellow sector will give 1 point => 1 * 2/7 = 2/7   points

landing on a purple sector will give 0 points => 0 * 2/7  = 0   points

landing on a red sector will give –1 point.  =>  - 1 * 2/7  = -2/7 points

Expected value  =  3/7 + 2/7 + 0 - 2/7

= 3/7

Expected value  =  3/7

3/7   < 1/2

=> game is not fair

If expected value = 3.5/7 = 1/2  then game will be fair

hence if we make 3.5 points for Landing on the blue sector

then game will be fair.

a=24; b=12

step-by-step explanation:

a/b=2: 1

a=2b

36/(1+2)=12

b=12

a=24

- both graphs increase on their domain.

- the graphs of both functions have the same x-intercept.

- neither graph has a y-intercept.