A balloon rises vertically at the rate of 10 ft. per second. If it encounters
a wind that gives a horizontal displace-
ment of 5 feet per second,
find (to the nearest whole degree)
the angle with the horizontal at
which the balloon rises.
a.
b.
find (to the nearest 10 feet) its
distance from the starting point
after one minute.

a) 63°

b) 600ft

Step-by-step explanation:

To solve the above question, we would be using Trigonometric function

a) Find (to the nearest whole degree)

the angle with the horizontal at

which the balloon rises.

This above question a is a right angled triangle that is solved for using Trigonometric function of tan

From the question, we told that,

Vertical distance ( opposite side) = 10 feet

Horizontal distance ( adjacent side) = 5 feet.

Tan θ = opposite side/ adjacent side

Tan θ = 10/5

Tan θ = 2

θ = arc tan (2) or tan -¹(2)

θ = 63.434948823°

θ = 63°

The angle with the horizontal at

which the balloon rises to the nearest whole degree is 63°

b) find (to the nearest 10 feet) its

distance from the starting point

after one minute.

Distance = Speed × time

Time is given in the question as 1 minute

We would convert it to seconds = 60 seconds

We are told in the question that the balloon rises vertically at the speed of 10ft/s

Distance = 10ft/s × 60seconds

Distance from the starting point per minute = 600ft

the answer is vanilla

step-by-step explanation: