A given line has the equation . What is the equation, in slope-intercept form, of the line that is perpendicular to the given line and passes through the point (0, 9)?

Step-by-step explanation:

The question is incomplete. Here is the complete answer.

A given line has the equation 2x + 12y = −1.

What is the equation, in slope-intercept form, of the line that is perpendicular to the given line and passes through the point (0, 9)?

General formula of equation of a line is exspressed as y = mx+c

m = gradient or slope  

c = intercept

Step 1: we need to first get the slope of the given equation of a line by rewriting the equation in standard form y = mx+c

2x + 12y = −1

12y = -1-2x

y = -1/12-2x/12

y = -1/6 x - 1/12

From the equation above, it can be seen that the slope (m) of tghe line is -1/6.

Since both lines are perpendicular, the slope of the unknown line will be;

M = -1/m

M = -1/(-1/6)

M = 6

Step 2: We will find the intercept c by substituting the point (0,9) and the slope into the equation y = mx+c

9 = 6(0)+ c

c = 9

Stwp 3: We will find the equation of the line perpendicular to the given line by substituting the value of m and c into the equation y = mx+c

y = 6x+9

y-6x = 9

The equation in slope-intercept form, of the line that is perpendicular to the given line and passes through the point (0, 9) is y-6x = 9

rotation point l

step-by-step explanation: