What is the value of b in the equation (y^-9)^b=y^45?

b = (log(y^45))/log(1/y^9) + (2 i π n)/log(1/y^9) for n element Z

Step-by-step explanation:

Solve for b:

(1/y^9)^b = y^45

Take the logarithm base 1/y^9 of both sides:

b = (log(y^45))/log(1/y^9) + (2 i π n)/log(1/y^9) for n element Z

< 4, -5>

step-by-step explanation:

starting from g. we move 4 right and then 5 down to get to h. that means the vector is < 4, -5>

its d. the first coordintaes are 10,32

step-by-step explanation: