How many grams of water would require 4000 joules of heat to raise its temperature from 65°C to 100°C? The specific heat of water is 4.181?

27.33 g water

Step-by-step explanation:

For this problem, we will need to use the equation for heat: q=mCΔT. Since we are given heat, change in temperature, and specific heat, all we have to do is plug them in to find grams.

4000J=m(4.181J/g°C)(100-65°C)              [find change in temperature]

4000J=m(4.181J/g°C)(35°C)    [divide both sides by specific heat and change in temperature]

m=27.33 g

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