The graph below shows a translation of preimage triangle vertex C to image triangle vertex C'. What is the algebraic rule for this translation?
A. (x, y) = (x+6,9+2)
B. (x, y) → (x-6,y-2)
C. (x, y) → (x -6,y-6)
D. (x, y) → (x+2,x+10)

Option (B)

Step-by-step explanation:

From the figure attached,

Triangle with vertex C' is a translated form of the triangle with vertex C.

Coordinates of pre-image C → (2 , 6)

Coordinates of the image C' → (-4, 4)

Rule followed from pre-image C to image C',

(2, 6) → (-4, 4)

(2, 6) → [(2 - 6), (6 - 2)]

(x, y) → [(x - 6), (y - 2)]

Therefore, rule given in option (B) is the answer.

15

step-by-step explanation:

we are given the following expression and we are to solve it and find the product:

-13 × (-5)

solving the given expression in the standard order of solving a mathematical expression, beginning with the opening of brackets and then multiplying the terms and changing their signs.

-3 × -5 = 15 (answer is positive because when negative is multiplied with negative, it gives a positive answer)

sorry not sure

step-by-step explanation: