Use the three conditions to show that function f(x)=2x^2 +3x - 1 is continuous at x=0.

f(x)  = 2x^2 +3x - 1

f'(x) = 4x + 3

f''(x) = 4

f(0) = 2(0)^2 + 3(0) - 1 = -1 (valid)

f'(0) = 4(0) + 3 = 3 (valid)

f''(0) = 4 (valid)

=> f(x) is continous at x = 0

  the correct choice is marked

step-by-step explanation:

the first two graphs show multiple turning points. the last graphs matches the description in every detail.

60

step-by-step explanation:

every triangle measures a total of 120 degrees. you have to find angle c. we know that isosceles triangles angles are equal. 60 degrees plus 60 degrees gives you 120.