How many integers are between sqrt 37 and 5*sqrt 11?

There are 10 integers between the given values

Step-by-step explanation:

We start by finding approximations of the two real values given that include square roots of non-perfect-square numbers:

then this point is located in between the integers 6 and 7 on the x-axis.

therefore, it is located between the integers 16 and 17 on the number line.

Then between , and , we have the following integers:

7, 8, 9, 10, 11, 12, 13, 14, 15, 16.

That is 10 integers

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

ok then what happened.