On a coordinate plane, 2 triangles are shown. The first triangle has points F (3, 2), H (4, 5), G (1, 2). The second triangle has points F prime (negative 2, 3), H prime (negative 5, 4), G prime (negative 2, 1). Quinton tried to transform triangle FGH according to the rule (x, y) → (–y, x). Which best describes his attempt? Correct. He transformed the triangle according to the rule (x, y) → (–y, x). Incorrect. He transformed the triangle according to the rule (x, y) → (y, –x) Incorrect. He transformed the triangle according to the rule (x, y) → (–y, –x) Incorrect. He transformed the triangle according to the rule (x, y) → (–x, –y)

  Correct. He transformed the triangle according to the rule (x, y) → (–y, x)

Step-by-step explanation:

Given

  F(3, 2), H(4, 5), G 1, 2)

  F'(-2, 3), H'(-5, 4), G'(-2, 1)

Find

  Whether the triangle was correctly transformed using the rule ...

  (x, y) → (–y, x).

Solution

For point F, we have ...

  x = 3

  y = 2

Then the rule tells us the point F' should be ...

  F' = (-y, x) = (-2, 3)

This is the point Quinton found for F', so his transformation was correct. (We can similarly verify that H' and G' are also correct.)

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

where are the choices?