Triangle ABC has vertices A(4,5), B(8,9), and C(6,7). What are the vertices of triangle A′B′C′ if triangle ABC is translated according to the algebraic description (x, y) → (x + 3, y – 2)?

A'(7,3), B'(11,7) and C'(9,5).

Step-by-step explanation:

The vertices of given triangle are A(4,5), B(8,9), and C(6,7).

Given rule of translation is

We need to find the vertices of triangle A'B'C'.

Now,

Therefore, the vertices of triangle A'B'C' are A'(7,3), B'(11,7) and C'(9,5).

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1