Write the equation of the line given the slope and a point through the line passes 5/3,(-3,-1) & 9/4,(3,0)

1.) Y = 5/3 X + 4

2.) Y = 9/4 X - 27/4

Step-by-step explanation:

Given the slope and the coordinate, linear equation of a line can be expressed by using general linear equation. Which is

Y = MX + C

Where the

Slope M = 5/3

Coordinate = (-3,-1) in which

X = -3, Y = -1

Substitute X, Y and M into the general linear equation to achieve C

-1 = 5/3(-3) + C

-1 = - 5 + C

C = 5 - 1

C = 4

Substitute C and M back into the general linear equation.

Therefore, the equation of the line given the slope and a point through the line passes 5/3, and (-3,-1) to be

Y = 5/3 X + 4

2.) Also,

Slope M = 9/4

Coordinate = (3,0) where X = 3, Y = 0

Substitute X, Y and M into the general linear equation to obtain C

0 = 9/4 (3) + C

C = - 27/4

Substitutes C and M back into the general linear equation

Therefore, the equation of the line given the slope and a point through the line passes 9/4 and (3,0)

Y = 9/4 X - 27/4

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step-by-step explanation: