At what point will the graph of the equations 3x +y =7&
y=1 intersect?

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Work Shown:

Substitute y = 1 into the first equation. Basically we replace every y with 1. From here we solve for x

3x+y = 7

3x+1 = 7

3x+1-1 = 7-1 .... subtracting 1 from both sides

3x = 6

3x/3 = 6/3 .... dividing both sides by 3

x = 2

We have x = 2 pair up with y = 1. The two equations intersect at (2,1)

As a check, plugging (x,y) = (2,1) into the first equation should lead to a true statement

3x+y = 7

3(2)+1 = 7

6+1 = 7

7 = 7 and it does lead to a true statement

The graph is shown below.

452,489 to the nearest thousand is 452,000

other answer is correct. i had used the radius of the radius somehow. a website: