If x + 2 is a factor of x^3 - 2ax^2 +16, then value of a is i) 3 ii) 1 iii) 4

ii) 1

Step-by-step explanation:

Let p(x) =

Given that x+2 = 0

Then => x = -2

Putting this in p(x)

p(-2) =

By remainder theorem , Remainder will be zero

0 = -8-8a+16

0 = -8a+8

-8a = -8

Dividing both sides by -8

=> a = 1

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

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step-by-step explanation: