Let q = demand for seats on a 500-seat airplane and p = price charged per ticket. Suppose that q = 600 - 3p and assume that the unit cost of flying a passenger is $50. To maximize profit from the flight, the airline should charge how much per ticket?

Step-by-step explanation:

Given the equation  q = 600 - 3p where;

q = demand for seats on a 500-seat airplane

p = price charged per ticket

Revenue = demand for seats * price charged per ticket i.e pq

Revenue = p * 600 - 3p ... 1

Cost of flying a passenger = unit cost *  demand for seats = 50q

Cost of flying a passenger = 50q ...2

Profit generated will be the revenue less cost i.e Revenue - cost

Profit generated = p(600 - 3p) - 50q

= p(600 - 3p) - 50(600-3p)

= 600p-3p²-30000+150p

= -3p²+750p-30000

Profit P = -p²+250p-10000

To maximize the profit, dP/dp = 0

-2p+250 = 0

-2p = -250

p = $125

To maximize profit, the airline should charge $125 per ticket

first option

a function is a relation in which an input is paired with exactly one output.

so, let's find the right answer.

in our first option, our inputs are january, february, and march. the outputs are 30, 28, and 25. each input has it's own output. this is correct!

our second option we know is incorrect, because ms. valverade has two outputs, dogs and cats. this is not a function.

our third option is incorrect as well. the yellow square has two ouputs, the square and the triangle.

lastly, in our fourth option, we see the number 7 two times with a different output. therefore, this is not a function.

remember: each input must be paired with only one output!

23

step-by-step explanation: