The tires of a go-kart are 1 m1 \text{ m}1 m1, start text, space, m, end text in circumference. The tires revolve 15151515 times per second. What is the distance the go-kart travels in 40404040 seconds?

Step-by-step explanation:

Distance traveled = speed*time taken

The total distance traveled around the tires is the circumference.

If the tire of a go-kart with circumference of 1m revolves 15 times per second, the speed of the go-kart will be 1*15 = 15m/s

Given the time taken by the go-kart to travel round to be 40 seconds;

Distance traveled by the go-kart = 15*40 = 600m

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)